Math, asked by vikashbettiah1, 5 months ago

Divide 2400 in the ratio. (a) 3:5 , (b) 5:7 , (c) 4:5:7​

Answers

Answered by aayushsharma7956
7

Answer:

1.  THE NUMBERS IN THE RATIO ARE 900 AND 1500

2.  THE NUMBERS  IN THE RATIO ARE 1000 AND 1400

3.  THE NUMBERS IN THE RATIO ARE 600,750 AND 1050

Step-by-step explanation:

1.

 RATIO GIVEN = 3:5

 NUMBER TO BE DIVIDED = 2400

 SO,

 LET THE COMMON RATIO BE x

  SO,

  A.T.Q.,

  3x+5x = 2400

   8x = 2400

  x = 2400/8

  x = 300

 3x = 900

 5x = 1500

 SO,

 THE NUMBERS IN THE RATIO ARE 900 AND 1500

2.

 RATIO GIVEN = 5:7

 NUMBER TO BE DIVIDED = 2400

 SO,

 LET THE COMMON RATIO BE x

 SO,

 A.T.Q.,

 5x+7x = 2400

 12x = 2400

  x = 2400/12

 x = 200

 5x = 1000

 7x = 1400

 SO,

 THE NUMBERS  IN THE RATIO ARE 1000 AND 1400

3.

 RATIO GIVEN = 4:5:7

 NUMBER TO BE DIVIDED = 2400

 SO,

 LET THE COMMON RATIO BE x

SO,

 A.T.Q.,

 4x+5x+7x = 2400

 16x = 2400

  x = 2400/16

  x = 150

  4x = 600

  5x = 750

  7x = 1050

  SO,

  THE NUMBERS IN THE RATIO ARE 600,750 AND 1050

I HOPE YOU UNDERSTOOD THE QUESTION!!!

                             !!!JAI SHREE KRISHNA!!!

Answered by BrainlyTopper97
105

\huge{\orange{\boxed{\boxed{\pink{\underline{\green{\mathscr{Answer:}}}}}}}}

a) 900 and 1500

b) 1000 and 1400

c) 600, 750 and 1050

{\underline{Step-by-step \ explaination:}}

{\underline{Given:}}

  • Total part = 2400

    a. Ratio (1st question) = 3:5

    b. Ratio (2nd question) = 5:7

    c. Ratio (3rd question) = 4:5:7

{\underline{To \ Find:}}

    a. Values of the ratios

    b. Values of the ratios

    c. Values of the ratios

{\underline{Analysis:}}

    a. Let the common multiple be 'x',

So, the numbers become 3x and 5x.

Equation formed:

3x + 5x = 2400

⇒ 8x = 2400

⇒ x = \frac{2400}{8}

⇒ x = 300

So, the numbers are:-

3x = 3 × 300 = 900

5x = 5 × 300 = 1500

_______________________________________________________

    b. Let the common multiple be 'x',

So, the numbers become 5x and 7x.

Equation formed:

5x + 7x = 2400

⇒ 12x = 2400

⇒ x = \frac{2400}{12}

⇒ x = 200

So, the numbers are:-

5x = 5 × 200 = 1000

7x = 7 × 200 = 1400

_______________________________________________________

c. Let the common multiple be 'x',

So, the numbers become 4x ,5x and 7x.

Equation formed:

4x + 5x + 7x = 2400

⇒ 16x = 2400

⇒ x = \frac{2400}{16}

⇒ x = 150

So, the numbers are:-

4x = 4 × 150 = 600

5x = 5 × 150 = 750

7x = 7 × 150 = 1050

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