Question

divide 243 into 3 part such that half of the first , one third of second part and 1/4 of third part are equal​

Answer 1

Answer:

54,81 and 108

Step-by-step explanation:

Let the  parts are x,y,z then

x/2=y/3=z/4

hence y=3x/2

and z=4x/2=2x

and x+y+z=243

putting values of y and z

x+3x/2+2x=243

Multiply by 2 in both sides

2x+3x+4x=486

9x=486

x=486/9=54

Hence y=3x/2=3*54/3=81

z=2x=54*2=108

hence three aprt are 54,81 and 108