Question

Divide 243 into 3 parts such that half of the first par, one-third of the second part and one-fourth of the third part are all equal ( in one variable )

Answer 1

let the first part be x
second= 3x/2
third= 2x

(since x/2=1/3*3x/2=2x/4)

a/q

x+3x/2+2x=243
9x/2=243
x=54

first part= 54
second= 3/2*54=81
third=2*54=108

Answer 2

Answer:

First Part = 54

Second = 3/2 × 54 = 81

Third = 2 × 54 = 108

Hope it will be helpful ✌️