Question

Divide 243 into 3 parts such that half of the first par, one-third of the second part and one-fourth of the third part are all equal.

Answer 1

let the numbers be x, y , zSo 1/2 x = 1/3 y = 1/4 z = k x = 2k , y = 3k , z = 4kAlso,x+y+z = 2432k+3k+4k = 2439k = 243k = 27So numbers are x = 54 , y = 81 , z = 108