Question

divide 243 into three parts such that half of the first number,1/3rd of the second number and 1/4th of all parts are equal.

Answer 1

here is your answer....

Answer 2

Answer:

Step-by-step explanation:

Let the numbers be a,b and c

Therefore 1/2a=1/3b=1/4c

Simplify them to get

6a/12=4b/12=3c/12

So 6a = 4b = 3c

Now take 6a equal to 4b

So b = 6a/4 or 3a/2

And now take 6a equal to 3c

So c = 6a/3 or 2a

Now as

Sum of a,b and c =243

Therefore

a + 3a/2 + 4a/2 = 243

9a=243*2=486

a=54

b=3/2*54=81

c=2*54=108