Question

Divide 243 into three parts such that half of the first part, one-third of the
second part and one-fourth of the third part are all equal.------- and if you like this question please follow me​

Answer 1

let the number be x y and z

so 1/3x= 1/3y =1/4z=I

x=2k y=3k z=4k

also

x+y+z=243

2k+3k+4k=243

9k=243

k=243÷9

k=27

soo

x=54 y=81 z= 108

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