Question

Divide 243 into three parts such that half of the first part, one-third of the
second part and one-fourth of the third part are all equal.
​

Answer 1

Answer:

let the numbers be x, y , z

So 1/2 x = 1/3 y = 1/4 z = k

x = 2k , y = 3k , z = 4k

Also,

x+y+z = 243

2k+3k+4k = 243

9k = 243

k = 27

So numbers are x = 54 , y = 81 , z = 108