Question

divide 243 into three parts such that half of the first part one third of the second part and one fourth of the third part are all equal.​

Answer 1

Answers

Let x be the number in the first part.

Let y be the number in the second part.

Let z be the number in the third part.

We know that

x + y + z = 243

Then “half of the first part, a third of the second part, and a fourth of the third part are all equal” means

x/2 = y/3 = z/4

Let's look at just one variable. We know that

x = (2/3)y

And

z = (4/3)y

So

(2/3)y + y + (4/3)y = 243

3y = 243

y = 81

Then

x = (2/3)(81)

x = 54

And

z = (4/3)(81)

z = 108

x, y, and z are our sections.

Answer 2

Step-by-step explanation:

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