Question

divide 243 into three parts such that haly of that half of the first part , one- third of the second part and one- fourth of the third part are all equal

Answer 1

Here a+b+c=243
a/2=b/3=c/4
Therefore, 3a=2b=3/2c
a+3a/2+2a=243
a=54
b=81
c=108