Question

divide 25 in two parts such that 2/3 of 1 part is equal to 10 less than twice the other part​

Answer 1

Answer:

10,15

Step-by-step explanation:

let, one part=y, another part=p

then,(2y/3)=2p-10

or,2y=3(2p-10)

or,y=(3/2)(2p-10)

or,y=3p-15

again,

y+p=25

or,3p-15+p=25

or,4p=25+15

or,4p=40

or,p=40/4

then,p=10

again,

y+p=25

or,y+10=25

or,y=25-10

or,y=15

Answer 2

Step-by-step explanation:

Let assume the values as 15,10

verify:

2/3x=2y-10

2×15/3=2×10-10

2×5=20-10

10=10

hence the verify proved that the assume values is correct