Divide 25 into 5 parts in A.P. such that the first and the last term are in the ratio 2:3. Then what will be it's 10th term?
Answers
AnswEr :
- Divide 25 into 5 parts in A.P. such that First term and Last Term are in Ratio 2:3
- Find the 10th Term of A.P.
Let the Terms be (a - 2d), (a - d) , a, (a + d), (a + 2d) where d is the difference.
• According to Question Now :
⇒ (a - 2d) + (a - d) + a + (a + d) + (a + 2d) = 25
⇒ a + a + a + a + a = 25
⇒ 5a = 25
- Dividing Both term by 5
⇒ a = 5
• Again According to Question :
⇒ 1st Term : 5th Term = 2 : 3
⇒ (a - 2d) / (a + 2d) = 2 / 3
- By Cross Multiplication
⇒ 3 × (a - 2d) = 2 × (a + 2d)
⇒ 3a - 6d = 2a + 4d
⇒ 3a - 2a = 4d + 6d
⇒ a = 10d
- Putting the Value of a = 5
⇒ 5 = 10d
- Dividing Both term by 5
⇒ 1 = 2d
⇒ d = 1 /2
⇒ d = 0.5
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➟ 10th Term of AP
➟ a + (n - 1)d
- Plugging the Values
➟ 5 + (10 - 1) × 0.5
➟ 5 + 9 × 0.5
➟ 5 + 4.5
➟ 9.5
჻ Hence, 10th Term of A.P. will be 9.5
Answer:
8.5
Step-by-step explanation:
(a-2d) +(a-d) +a+(a+d) +(a+2d)=25
5a-2d-d+d+2d=25
5a=25
a=5.
First term is a-2d
Last term is a+2d
Their ratio is 2:3
(a-2d) / (a+2d) =2/3
3a - 6d = 2a + 4d
-6d - 4d = +2a - 3a
-10d = - a
(a = 5)
-10/-5 =d
d= 0.5.
FIND THE 10th Term
The tenth term will be a + 7d
Because
a + 2d = 5th term
a + 3d = 6th term
a + 4d = 7th term
a + 5d = 8th term
a + 6d = 9th term
a + 7d = 10th term...
So,
For 10th term
a=5, d=0.5
a +7d = (5) + 7(0.5) = 8.5