Math, asked by Ayanhusain, 1 year ago

Divide ₹25000 between A,B and C so that A get 7/8 of B and C gets 2/3 of A and B

Answers

Answered by sibhiamar
89
divide rupee 25,000 between A, B and C
so, A + B + C = 25000.............(1)

A gets 7/8 of B
so, A = 7B/8

C gets 2/3 of A and B
so, C = (2/3) × (A+B)
C = (2/3) × ((7B/8)+B)
C = (2/3) × ((7B+8B)/8)
C = (2/3) × (15B/8)
C = 5B/4

substitute A and C in (1)
(7B/8) + B + (5B/4) = 25000
(7B + 8B + 10B)/8 = 25000
25B/8 = 25000
B = 25000 × (8/25)
B = 8000

A = (7 × 8000)/8
A = 7000

C = (5 × 8000)/4
C = 10000

A gets 7000, B gets 8000, C gets 10000
Answered by sitad7091
27

divide rupee 25,000 between A, B and C

so, A + B + C = 25000.............(1)

A gets 7/8 of B

so, A = 7B/8

C gets 2/3 of A and B

so, C = (2/3) × (A+B)

C = (2/3) × ((7B/8)+B)

C = (2/3) × ((7B+8B)/8)

C = (2/3) × (15B/8)

C = 5B/4

substitute A and C in (1)

(7B/8) + B + (5B/4) = 25000

(7B + 8B + 10B)/8 = 25000

25B/8 = 25000

B = 25000 × (8/25)

B = 8000

A = (7 × 8000)/8

A = 7000

C = (5 × 8000)/4

C = 10000

A gets 7000, B gets 8000, C gets 10000

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