Question

divide 25000 between A,B andC so that Aget 7by8 ofB andC gets 2by3 of AandB​

Answer 1

Answer:

Heya Mate!!

♦a=7000

b=8000

c=10000

—>Answer:a+b+c=25000

a+b+c=250007000+8000+10000=25000

Step-by-step explanation:

as per given conditions we will get

a=7b/8 (1)

a/b=7/8

as per other condition

c=2(a+b)/3 (2)

a+b+C =25000(3)

by putting the value of (1) and (2) in (3)

7b/8+b+2(a+b)/3=25000

7b/8+b+2(7b/8+b)/3=25000

(7b+8+b)(1+2/3)=25000

(7b+8b)/8(5/3)=25000

(15b/8)x5/3=25000

75b/24=25000

b=25000x24/75

b=8000

Now, a=7b/8

a=7x8000/8=7000

c=(a+b)x2/3

c=(7000+8000)x2/3

c=15000x2/3=10000