Math, asked by drishtitabanik, 1 year ago

Divide 252 into two parts such that one-third of one part may exceed one-seventh of the other part by 60

Answers

Answered by biswajit2006
2
here is the answer . please give me a thank
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Answered by MarvelEdge17
0

Answer:

50.4 & 201.6

Step-by-step explanation:

Let one part be x. The other part will be 252-x

1/3 of x is greater than 1/7(252-x) by 60

So x/3 = (252-x)/7 +60

x/3 = (252-x+420)/7

7x = 3(-x+672)

10x = 2016

x = 201.6

The other part is 252 - 201.6 = 50.4

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