divide 26 into two parts such that sum of their square is 133
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Answer:
Let x and y be the two parts of the number 10
∴x+y=10 ...... (i)
According to the question,
Let A=2x+y
2
=2x+(10−x)
2
=2x+100+x
2
−20x
=x
2
−18x+100
On differentiating w.r.t. x, we get
dx
dA
=2x−18
For max or min of A,
Put
dx
dA
=0=2x−18
⇒x=9
Now,
dx
2
d
2
A
=2>0 (min)
On putting x=9 in Eq. (i), we get
y=1
∴(x,y)=(9,1)
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