Question

divide 26 into two parts whose sum of squares is 346​

Answer 1

Answer:

Let one part be x and the other be 26-x

ACQ,

X^2 + (26-X)^2 = 346

X^2 + x^2 + 676 - 52x = 346

2x^2 - 52x + 330 = 0

=> x^2 - 26x + 165 = 0

X^2 - 15x - 11x + 165 =0

X ( x - 15) - 11x (x - 15) =0

(x-15)(x-16) =0

X = 15

X = 11

Therefore the two parts of 26 are 15 and 11

{15 + 11 = 26}

Step-by-step explanation:

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Answer 2

Answer:

Ist part= x

2nd part = 26-x

A.T.Q.:

x^2 + ( x-26)=346

x^2 + x^2 +676 -52x=346

2x^2 -52x+330=0

2(x^2-26x+165)=0 Therefore,2 is not equal 0

So, x^2 -26x +165=0

x^2-15x-11x+165=0

x(x-15)-11(x-11)=0

So,x=15

x=11

So,15+11=26