Divide 27 into three parts which are in an AP, such that product of last two is 65.
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Suppose, a-d,a, and a+d are three parts
Now, a - d + a + a + d=27
or, 3a=27
or, a=27/3=9
Again, ( a - d)( a + d)=65
or, a^2 - d^2=65
or, 81 - d^2=65
or, d^2= 16
or, d=4.
So numbers are 5,9 and 13.
Now, a - d + a + a + d=27
or, 3a=27
or, a=27/3=9
Again, ( a - d)( a + d)=65
or, a^2 - d^2=65
or, 81 - d^2=65
or, d^2= 16
or, d=4.
So numbers are 5,9 and 13.
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