Question

divide 27 into two parts such that the sum of their reciprocal is 3/20

Answer 1

let two parts be x and y
so x+y=27
A2q,
1/x+1/y=3/20
After putting x+y=27
y=180/x
putting y=180/x in eq x+y=27
x^2-27x+180
after solving
x=15 & 12
these are two parts
I hope it'll help u

Answer 2

let the 2 parts be x and 27-x
A.TQ.,
1/X+1/27-X =3/20
on taking LCM,
27-X+X/X(27-X) =3/20.
x^2-27x+180=0
x^2-12x-15x+180=0
hence,
x=12 or 15
when x=12 , other part =27-12=15
when x=15 , other part =27-15=12
so ,two parts are 12 and 15

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