Question

Divide 27 into two parts such that the sum of their reciprocals are 3/20

Answer 1

Answer:

Step-by-step explanation:

let two parts be x and y

so x+y=27

A2q,

1/x+1/y=3/20

After putting x+y=27

y=180/x

putting y=180/x in eq x+y=27

x^2-27x+180

after solving

x=15 & 12

Answer 2

Let number = x

Another number = 27 - x

According to question;

1/x + 1/(27 - x) = 3/20

(27 - x + x)/(27x - x²) = 3/20

Cross-multiply,

20(27) = 3(27x - x²)

540 = 81M - 3x²

x² - 27x + 180 = 0

x² - 15x - 12x + 180 = 0

x(x - 15) -12(x - 15) = 0

(x - 12) (x - 15) = 0

x = 12, 15