Question

Divide 28 in two part such that 6/5 of one part is equall to 2/3 of the other

Answer 1

let first part be x second part =28-x

ATQ

6/5*x=2/3* (28-x)

6x/5=56/3-2x/3

6x/5+2x/3=56/3

(18x+10x)/15=56/3

28x=56/3*15

x=(56*5)/28

x=10

28-x=28-10-18

Ist part=10

2nd part=18



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Answer 2

Answer:

numbers are 10 and 18

Step-by-step explanation:

let one part be x therefore another part be 28-x

6/5 x = 2/3 ( 28-x)

18x = 10(28 -x)

18x + 10x = 280

28x = 280

x = 10

there numbers are 10 and 28-10= 18