Question

divide 28 into two parts in such a way that 6/5of one part is equal to 2/3of the other​

Answer 1

Let one part of 28 be 'y'

Therefore the other part = 28 - y

So,

6/5 × y = 2/3 (28 - y)

=> (6/5 × y) / 2/3 = 28 - y

=> 9/5× y = 28 - y

=> 9/5× y + y = 28

=> 14y /5 = 28

=>14 y = 28 × 5

=> 14 y = 140

=> y = 140/14

=> y = 10

Therefore one part of 28 = 10

The other part = 28 - 10 = 18

Hope this answer was the needful...pls do mark this answer as the brainliest.