Question

Divide 282 into two parts such that the eight part of the first and the fifth part of the second are in the ratio 4:3.

Answer 1

Let first part is x Second part is 282-x 8th part is x/8 5th part is 282-x/5 Given condition is x/8:282-x/5=4:3 5x/8(282-x)=4/3 15x=32(282-X) 15x=9024-32x 47x=9024 X=192 First part is 192 Second part is 282-192=90 Hope this helped u