Question

divide 286 into four parts such that the first part increased by 1,the second decreased by 2 the third multiplied by 3 and the fourth divided by 4 will give same result in each case.

Answer 1

let the 4 parts be a, b ,c , d

a+b+c+d = 286

also
a+1=b-2=3c=d/4

either add 1 or subtract 2 from the first equation

a+b+c+d+1 =286+1
substituting values,
a+1 = b-2
c= (b-2)/3
d= 4b - 8

and solve it for b

Answer 2

let 286 is divided into four parts
let think the number be x
first part =x+1
second part =x-2
third part=x×3=
fourt part=x÷4