Question

divide 286 into four parts such that the first part increased by 1,the second decreased by 2 the third multiplied by 3 and the fourth divided by 4 will give same result in each case. (Hint: Assume the result in each case to be x)

Answer 1

Let the 4 numbers be a b c & d.
Now a+b+c+d=286.
a+1=b-2=c*3=d/4

Hence We Get,
b=a+3
c=(a+1)/3
d=4a+4

Adding all the above
a+b+c+d=286
a+a+3+(a+1)/3+4a+4=286
Solve the above equation and we get a=45

similarly by inserting this we get
a b c & d as 44 47 15 & 180