Divide 29 into two parts so that sum of the squares of the parts is 425
Answers
Answered by
22
Let the two parts be x and 29-x
so according to question x² + (x-29)² = 425⇒ x² + (29 - x)² = 425⇒ x² + 841 + x² - 58x = 425⇒2x² - 58x + 416 = 0⇒ x² - 29x + 208 = 0⇒ x² - 13x - 16x + 208 = 0⇒ x(x - 13) - 16(x - 13) = 0⇒ (x - 16)(x - 13) = 0 so x = 16 or 13
Pl mark brainiest if it helped you.
so according to question x² + (x-29)² = 425⇒ x² + (29 - x)² = 425⇒ x² + 841 + x² - 58x = 425⇒2x² - 58x + 416 = 0⇒ x² - 29x + 208 = 0⇒ x² - 13x - 16x + 208 = 0⇒ x(x - 13) - 16(x - 13) = 0⇒ (x - 16)(x - 13) = 0 so x = 16 or 13
Pl mark brainiest if it helped you.
Similar questions