Question

divide 29 into two parts so that sum of there squares is 425​

Answer 1

Answer:

13,16

Step-by-step explanation:

let the numbers be x and (29-x)

given:

x^2+(29-x)^2=425

x^2+841-58x+x^2=425

2x^2-58x+416=0

dividing by 2

x^2-29x+208=0

x^2-16x-13x+208=0

x(x-16)-13(x-16)=0

(X-16)(X-13)=0

x=16,13

Answer 2

Let one part be x and other (29-x)

x² + (29-x)² = 425

x²+29²+x²-58x =425

2x²-58x +841 =425

2x²-58x +416=0

x²-29x+208=0

x²-16x-13x+208=0

x(x-16)-13(x-16)=0

(x-13)(x-16)=0

x=13,16.

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