divide 29 into two parts so that the product of the two parts is 208
represent in quadratic equation
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16 or13
Step-by-step explanation:
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Let x and y be the two numbers.
x + y = 29 … eq(i)
xy = 208 … eq(ii)
Finding the value of y from eq(i) and substituting in eq(ii)
y = 29 - x
=> xy = x(29 - x) = 29x - x^2 = 208
=> x^2 - 29x + 208 = 0
Alternative Solution
=================
Let α and β be zeros of quadratic equation. So,
α + β = 29
αβ = 208
Therefore, the quadratic equation is
x^2 - (α+β)x + αβ = 0
=> x^2 - 29x + 208 = 0
x + y = 29 … eq(i)
xy = 208 … eq(ii)
Finding the value of y from eq(i) and substituting in eq(ii)
y = 29 - x
=> xy = x(29 - x) = 29x - x^2 = 208
=> x^2 - 29x + 208 = 0
Alternative Solution
=================
Let α and β be zeros of quadratic equation. So,
α + β = 29
αβ = 208
Therefore, the quadratic equation is
x^2 - (α+β)x + αβ = 0
=> x^2 - 29x + 208 = 0
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