Question

Divide 29 into two parts so that the sum of the squares of the parts is 425.find the value of each part

Answer 1

Answer:

first part=16 and second part=13

Step-by-step explanation:

let first part=x

second part=y

x+y=29=> x=29-y

x^2+y^2=425

(29-y)^2+y^2=425

841-58y+2y^2=425

y^2-29y+208=0

then y=16 and 13