Question

divide 29 into two parts so that the sum of the squares of the two parts is 425

Answer 1

let one number = x
second number = 29-x
sum of the squares the numbers = 425
x² +(29-x)² =425
x²+(29)²-58x+x²-425=0
2x²-58x +841-425=0
2x²-58x+416=0
divide each term with 2

x²-29x +208=0

x²-16x -13x+13*16=0

x(x-16) -13(x-16)=0
(x-16)(x-13) =0
x-16 =0 or x-13 =0
x= 16 or x= 13

therefore
one number =x = 16
second number = 29- 16 = 13

Answer 2

Step-by-step explanation:

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