divide 29 into two parts such that sum of their squares is 425
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Answered by
1
13 and 16 will be ur ans
Answered by
16
Hey
Here is your answer,
When 29 is divided , it can be written as x and 29-x.
According to the question,
x^2 + (29-x)^2=425
x^2+841+x^2-58x = 425
2x^2 - 58x = 425-841
2x^2 - 58x = 416
Divide the equation by 2
x^2 - 29x - 208 =0
x^2 -13x -16x -208=0
x(x-13) -16(x-13)=0
x =13
x=16
The numbers are 13 and 16.
Hope it helps you!
Here is your answer,
When 29 is divided , it can be written as x and 29-x.
According to the question,
x^2 + (29-x)^2=425
x^2+841+x^2-58x = 425
2x^2 - 58x = 425-841
2x^2 - 58x = 416
Divide the equation by 2
x^2 - 29x - 208 =0
x^2 -13x -16x -208=0
x(x-13) -16(x-13)=0
x =13
x=16
The numbers are 13 and 16.
Hope it helps you!
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