Question

divide 2x^2+x-20 by x+3 and verify by division algorithm​

Answer 1

Step-by-step explanation:

2x^2+x-20/X+3=

2x-5+remainder=-5

division algorithm:-

a=bq+r

therefore

x+3×2x-5=2x^2-5x+6x-15

now add remainder to get 2x^2+x-20 which is our a

therefore LHS=RHS

Therefore satisfied