Math, asked by neenasamra, 2 months ago

divide 2x(3x+3) (3x+6) (x+3) by x(2x+4)​

Answers

Answered by abhishekshibu9267
1

Answer:

9x^2 + 36x + 27

Step-by-step explanation:

2x(3x+3) (3x+6) (x+3) / x(2x+4)​

2x(3x+3) (3x+6) (x+3) / 2x(x+2)

(3x+3) (3x+6) (x+3) / (x+2)

(3x+6)(3x+3)(x+3) / (x+2)

3(x+2). 3(x+1)(x+3) / (x+2)

3 x 3(x+1)(x+3)

9(x+1)(x+3)

9(x^2 + 3x + x + 3)

9(x^2 + 4x + 3)

9x^2 + 36x + 27

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