Question

divide 2x^4+8x^3+7x^2+4x+3 by x+3

Answer 1

Given,

p (x) = 2x^4+8x^3+7x^2+4x+3

f (x) = x+3

x+3 = 0

x = -3.

substitute the value of x in p (x).

=) 2 (3)^4+8 (3)^3+7 (3)^2+4 (3)+3
=) 2 (81) + 8 (27) + 7 (9) + 12+3
=) 162+216+63+36
=) 477.

Answer 2

I hope this may help you out :)