Question

Divide 2x² + 3x + 1 by x+2​

Answer 1

Answer:

answer :x

Step-by-step explanation:

step 1: factorise 2x^2+3x+1

RULE: WE NEED TO FIND TWO NUMBERS SUCH THAT IF WE ADD THEM WE GET 3 AND MULTIPLY THEM WE GET 2

THE NUMBERS ARE: 2,1 (2*1)=2 AND (2+1)=3

2x^2+3x+1

=2x^2+2x+1x+1

=2x(x+1) 1(x+1)

=[(2x+1) (x+1)] /(x+2)

=(x+x+1)(x+1)/(x+2)

=x+(x+1) (x+1)/(x+1) (x+1)

answer :x

Answer 2

Answer:

2x³ +3x²  +2x+1  /  x

Step-by-step explanation:

2x² + 3 x + 1 ÷ x + 2  

To add or subtract expressions, expand them to make their denominators the same. Multiply 2x²  +3x+2 times x /x.

(2 x ² + 3 x + 2)  x / x + (1 /x)

 

Since (2x ²+3x+2) x / x   and  (1/x) have the same denominator, add them by adding their numerators.

(2x ²+3x+2)x+1    / x

​Do the multiplications in (2x+3x+2)x+1.

2x³ +3x²  +2x+1  /  x

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