Math, asked by SreehariAnil1161, 11 months ago

Divide 2x⁴+3x³-2x²-9x-12 by x²-3 and verify the division algorithm

Answers

Answered by nandnisingh7050
28

Answer:

Now, according to division algorithm

Dividend = Divisor × Quotient + Reminder

2x^4+3x^3-2x^2-9x-12 = x^2-3 × 2x^2+3x+4 + 0

solve it......

Hope it will help u !! ❤️❤️

Attachments:
Answered by dikshaagarwal4442
0

Answer:

The answer will be (2x² + 3x +4)

Step-by-step explanation:

  • Factorize the polynomial:

        The given polynomial is = 2x⁴+3x³-2x²-9x-12

                                                 = (2x⁴ - 2x² - 12) + (3x³ - 9x)

                                                 = 2(x⁴ - x² - 6) + 3x(x² - 3)

                                                 = 2{x⁴ - (3-2)x² - 6} + 3x(x² - 3)

                                                 = 2(x⁴ - 3x² + 2x² - 6) + 3x(x² - 3)

                                                 = 2{x²( x²-3) + 2(x² - 3)} + 3x(x² - 3)

                                                 = 2( x²-3)(x²+2) + 3x(x² - 3)

                                                 = (x² - 3){2(x²+2) + 3x}

                                                 = (x² - 3)(2x² + 3x +4)

  • Dividing it by x²-3 we get, (x² - 3)(2x² + 3x +4)/(x²-3)

                                                     = (2x² + 3x +4)

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