Question

divide 2X4+X3-14X2-19X-6 by X2+3X+2​

Answer 1

Step-by-step explanation:

Given :-

$2 {x}^{4} + {x}^{3} - 14 {x}^{2} - 19x - 6$

${x}^{2} + 3x + 2$

Quationt=

$2 {x}^{2} - 5x - 3$

Remainder=

$0$

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