Divide (2y4 - 3y3 + 5y - 4) ÷ (y - 1)
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Answered by
9
Answer:
2-3 0 5 -4
2-1-14
---------------
2-1-1 4 0
Answered by
7
Given,
(2y⁴-3y³+5y-4) is the dividend and (y-1) is the divisor.
To find,
The quotient when (2y⁴-3y³+5y-4) is divided by (y-1).
Solution,
We can simply solve the above-given question by using synthetic division for finding the quotient.
We will divide (2y⁴-3y³+5y-4) by (y-1).
The given polynomial can be written as 2y⁴-3y³+0y²+5y-4 in standard form.
We will use the standard form while dividing. On synthetic division we got 2y³−y²−y+4 as the quotient.
Hence, the quotient when (2y4 - 3y3 + 5y - 4) is divided by (y - 1) is 2y³−y²−y+4.
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