divide :- (2y4-3y3+5y-4)÷ (y-7)
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Answer: 2y4 - 3y3 + 5y - 4 = 2y3( y - 1)+ 2y3 - 3y3 + 5y - 4
= 2y3( y - 1) - y2 ( y - 1) - y2 + 5y - 4
= 2y3( y - 1) - y2 ( y - 1) - y ( y - 1) + 4y - 4
= (2y3 - y2 - y + 4) (y - 1)
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