Question

divide 2y⁴-7y³+7y²-6y+10by(y-2)​

Answer 1

Answer:

REMAINDER IS 138

Explanation:

We will solve this using remainder theorem method,

p(x) = 2y⁴-7y³+7y²-6y+10

Step 1 = Let us find out the root of the divisor

g(x) = y-2

y-2 = 0

y= -2

Step 2 = Let us find the remainder

p(-2) = 2(-2)⁴-7(-2)³+7(-2)²-6(-2)+10

        = 2(16) - 7(-8) + 7(4) +12 +10

       = 32 + 56 + 28 + 12 + 10

       = 138

Remainder = 138