Question

Divide 3,740 in three parts in such a way that half of the first part, one-third of the second part
and one-sixth of the third part are equal.​

Answer 1

Step-by-step explanation:

Let the three parts be x, y and z.

Given,

x + y + z = 3740 ---(1)

$\frac{x}{2} = \frac{y}{3} = \frac{z}{6} \\ 3x = 2y = z \: - - - (2)$

Substituting 2 in 1,

$x + \frac{3x}{2} + 3x = 3740 \\ 4x + \frac{3x}{2} = 3740 \\ 8x + 3x = 3740 \times 2 \\ 11x = 7480 \\ x = 680$

3x = 2y

3 × 680 = 2 × y

3 × 340 = y

y = 1020

3x = z

z = 3 × 680 = 2040