Divide (3+x-2x^2) by (x+1)
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Let p(x) = 3+x-2x²
=> p(x) = -2x²+x+3 (standard form)
Now, given g(x) = x+1
=> x = -1
Putting the value of x in the above equation.
We get, p(-1) = -2(-1)²+(-1)+3
=> -2-1+3
=> -3+3
=> 0
Hence, (3+x-2x^2)/(x+1) = 0
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