Question

Divide (3-x+2x²+x³-3x⁴) by (2-x) and verify by division algorithm.

Answer 1

The answer is provided in the attachment .... kindly Refer to it 

hope it helps ..... 

CHEERS#

Answer 2

Given:

$\bold{\frac{3-x+2x^2+x^3-3x^4}{2-x}}$

To Find:

Divide by division algorithm

Solution:

$\Rightarrow \frac{3-x+2x^2+x^3-3x^4}{2-x}$

First, we rearrange the value:

$\Rightarrow \frac{-3x^4+x^3+2x^2-x+3}{2-x}$

After arranging the value we divide:

$\Rightarrow \frac{-3x^4+x^3+2x^2-x+3}{2-x}= 3x^3+5x^2+8x+17 +\frac{-31}{2-x}$