Question

divide 3 x square minus x cube minus 3 X + 5 by X - 1 - x square and verify the division algorithm answers

Answer 1

Hey dear !!


Refer the attachment above !!



Now,


We have to verify the division algorithm.

We know that ,

Dividend = Divisor x Quotient + Remainder

(-x³ + 3x² - 3x + 5 )= (-x²+x-1)*(x - 2)+3

Taking R.H.S

-x² + x -1 * (x -2) +3

-x³ + 2x² + x² - 2x - x + 2 + 3

-x³ + 3x² - 3x + 5

we get,

L.H.S = R.H.S

We have verified it .



Thanks !!



[ Be Brainly ]

Answer 2

Answer:

Step-by-step explanation:

The polynomials presented are not in standard form, as should be noted. We initially write the dividend and divisor in descending order of their degrees before performing division.

Divisor = -x2 + x - 1  and dividend = -x3 + 3x2 - 3x + 5.

Since degree (3) = 0 < 2 Equals degree (-x2 + x - 1), we stop here. Consequently, quotient = x - 2;

                       remainder = 3.

Now, the formula reads as follows:

Dividend= Divisor* Quotient + Remainder

              =  (-x2 + x - 1) (x - 2) + 3

              = -x3 + x2 - x + 2x2 - 2x + 3

               = -x3 + 3x2 - 3x + 5.

The division algorithm is validated in this manner.

#SPJ3