Divide 30 (dbc + ab c + abc?) by 6abc
Answers
Answered by
1
Answer:
Step-by-step explanation:
30
(
a
2
b
c
+
a
b
2
c
+
a
b
c
2
)
=
2
×
3
×
5
[
(
a
×
a
×
b
×
c
)
+
(
a
×
b
×
b
×
c
)
+
(
a
×
b
×
c
×
c
)
]
=
2
×
3
×
5
×
a
×
b
×
c
(
a
+
b
+
c
)
Thus
30
(
a
2
b
c
+
a
b
2
c
+
a
b
c
2
)
÷
6
a
b
c
=
2
×
3
×
5
×
a
b
c
(
a
+
b
+
c
)
2
×
3
×
a
b
c
=
5
(
a
+
b
+
c
)
Alternatively
30
(
a
2
b
c
+
a
b
2
c
+
a
b
c
2
)
÷
6
a
b
c
=
30
a
2
b
c
6
a
b
c
+
30
a
b
2
c
6
a
b
c
+
30
a
b
c
2
6
a
b
c
=
5
a
+
5
b
+
5
c
=
5
(
a
+
b
+
c
)
Answered by
0
30(abc+abc+abc)/6abc
30(3abc)/6abc
90abc/6abc
(90/6)abc
15abc
I hope this helps
30(3abc)/6abc
90abc/6abc
(90/6)abc
15abc
I hope this helps
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