Math, asked by dipikatandi40, 11 months ago

Divide 300
into three parts
such that
the second part is half of the first
part and the third part is 3 time of
the second part find the three
diterent parts​

Answers

Answered by mimiij
2

Answer:

100

Step-by-step explanation:

Answered by adarshdutta2007
2

Answer:

Step-by-step explanation:

let the first=x

then second=x/2

third=3x/2

now sum of all=300

x+x/2+3x/2=300

(2x+x+3x)/2=300

6x=300×2

x=600/6=100

then first =100

Second =100/2=50

third=3×100/2=150

Similar questions