Question

Divide 300 into three parts such that the second part is half of the first part and the third part is 3 times the second part. Find the three different parts.

Answer 1

Let the first part be x. Therefore second part =x/2 And third part=3*x/2 Given, x+x/2+3*x/2=300 => x=100 First no.= 100 Second no.= 50 Third no.=150

Answer 2

Let the first part be 'x'

Second part : ½x = x/2

Third part : 3 × x/2 = 3x/2

Now,
1st part + 2nd part + 3rd part = 300

x + x/2 + 3x/2 = 300
6x/2 = 300
x = 300 × 2/6
x = 100


So,
1st part = x = 100
2nd part = x/2 = 100/2 = 50
3rd part = 3x/2 = 3×100/2 = 150