Question

divide 300 into three parts such that the second part is half of the third part is 3 timesof the second part. find the three different parts.​

Answer 1

Answer:

Let the first part be 'x'

Second part : ½x = x/2

Third part : 3 × x/2 = 3x/2

Now,

1st part + 2nd part + 3rd part = 300

x + x/2 + 3x/2 = 300

6x/2 = 300

x = 300 × 2/6

x = 100

So,

1st part = x = 100

2nd part = x/2 = 100/2 = 50

3rd part = 3x/2 = 3×100/2 = 150

Answer 2

Answer:

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Step-by-step explanation:

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