Question

divide 3010rupees among a, B, c in such way that a gets doubled of what b, B gets doubled of c and what's c gets

Answer 1

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Answer 2

A gets Rs 1720

B gets Rs 860

C gets Rs 430

Let A get Rs a

B get Rs b

and, C get Rs c.

Total money to be divided amongst A, B and C = Rs 3010

So, a + b + c = 3010         ...(1)

Also, A gets double of what B gets, so we can represent this statement as:

a = 2b                                  ...(2)

And, B gets double of what C gets, again we can represent it as:

b = 2c

⇒c = b/2                              ...(3)

Substituting the value of a = 2b (from eqn. (2)) and c = b/2 (from eqn. (3)), in eqn. (1), we get:

2b + b + b/2 = 3010

⇒7b/2 = 3010

⇒ b = (3010×2)÷7 = Rs 860

So, B gets Rs 860.

Putting the value of b in eqn. (2), we get the value of a as:

a = 2b = 2×860 = Rs 1720

Again, putting the value of b in eqn. (3), we get the value of c as:

c = b/2 = Rs (860/2) = Rs 430