Question

Divide 315 into 2 parts such that 2 times 1 part is equal to 7 times the other

Answer 1

First part = x

2nd prt = y

2x = 7y

x = 7y/2

x + y = 315

7y/2 + y = 315

7y + 2y = 315 x 2

9y  = 315 x 2

y = 35 x 2 = 70

x = 7y/2 = 490/2 = 295

Answer 2

Solution -

Let's assume one part as x

So, the second part as 315 - x

According to Question,

Given : 2 × One part = 7 × Second Part

2(x) = 7(315 - x)

⇒ 2x = 2205 - 7x [By transposition]

⇒ 2x + 7x = 2205

⇒ 9x = 2205        [By transposition]

⇒ x = 2205 / 9

⇒ x = 245

Required Numbers -

x = 245

315 - x = 315 - 245 = 70

Hence, the required numbers are 245 and 70

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