Question

Divide 32 into two parts such that 5 times one part added to 6 times gives 164

Answer 1

Question?

Divide 32 into two parts such that 5 times one part added to 6 times gives 164.

Answer:-

• x = 28
• y = 4

Step by Step Explaination:-

$\large \sf \purple{Let's \: Assume:- }$

• 32 be divided into x and y such that:-

$\leadsto\mathtt{x + y = 32 ------ (1)</p><p>}$

$\leadsto\mathtt{y = 32 - x}$

$\leadsto\mathtt{5x + 6y = 164 -----(2)}$

$\large{\underline{\sf{\green{Solving (1) and (2) }}}}$

$\implies \mathtt{5x + 6 (32-x) = 164}$

$\implies \mathtt{5x + 192 - 6x = 164}$

$\implies \mathtt{6x - 5x = 192 - 164}$

$\implies \mathtt{x = 28}$

$\large{\underline{\sf{\orange{So \: now}}}}$

$\implies \mathtt{y = 32 - x}$

$\implies \mathtt{y = 32 - 28}$

$\implies \mathtt{y = 4}$

$\large {\boxed{ \sf{ \pink{Therefore, two \: numbers \: are \: 28 \: and \: 4.}}}}$

Answer 2

$\huge { \boxed{ \rm{ \red{Question? }}}}$

Divide 32 into two parts such that 5 times one part added to 6 times gives 164.

$\huge { \boxed{ \rm{ \green{Answer:- }}}}$

Let 32 be divided into x and y such that -

• x + y = 32 ...(1)

• y = 32 - x

Given that,

• 5x + 6y = 164 ...(2)

Solving (1) & (2),

• 5x + 6 (32-x) = 164

• 5x + 192 - 6x = 164

• 6x - 5x = 192 - 164

• x = 28

So now,

• y = 32 - x

• y = 32 - 28

• y = 4